Textbooksolution for Multivariable Calculus 8th Edition James Stewart Chapter 14.7 Problem 57E. We have step-by-step solutions for your textbooks written by Bartleby experts!
Move all terms containing to the left side of the from both sides of the write as a fraction with a common denominator, multiply by .Step write as a fraction with a common denominator, multiply by .Step each expression with a common denominator of , by multiplying each by an appropriate factor of .Step the numerators over the common
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Let be a polynomial of degree 4, with , and . Then the value of is

Wecan write this in terms of a Random Variable, X, = "The number of Heads from 3 tosses of a coin": P(X = 3) = 1/8 ; P(X = 2) = 3/8 ; P(X = 1) = 3/8 ; P(X = 0) = 1/8 ; And this is what it looks like as a graph: It is symmetrical! Making a Formula. Now imagine we want the chances of 5 heads in 9 tosses: to list all 512 outcomes will take a long

Dado um polinômio px, temos que seu valor numérico é tal que x = a é um valor que se obtém substituindo x por a, onde a pertence ao conjunto dos números reais. Dessa forma, concluímos que o valor numérico de pa corresponde a px onde x = a. Por exemplo, dado o polinômio px = 4x² – 9x temos que seu valor numérico para x = 2 é calculado da seguinte maneira px = 4x² – 9x p2 = 4 * 2² – 9 * 2 p2 = 4 * 4 – 18 p2 = 16 – 18 p2 = –2 Se, ao calcularmos o valor numérico de um polinômio determinarmos pa = 0, temos que esse número dado por a corresponde à raiz do polinômio px. Observe o polinômio px = x² – 6x + 8 quando aplicamos p2 = 0. p2 = 2² – 6 * 2 + 8 p2 = 4 – 12 + 8 p2 = 12 – 12 p2 = 0 Dessa forma, percebemos que o número 2 é raiz do polinômio px = x² – 6x + 8, pois temos que p2 = 0. Exemplo 1 Dado o polinômio px = 4x³ – 9x² + 8x – 10, determine o valor numérico de p3. p3 = 4 * 3³ – 9 * 3² + 8 * 3 – 10 p3 = 4 * 27 – 9 * 9 + 24 – 10 p3 = 108 – 81 + 24 – 10 p3 = 41 O valor de px = 4x³ – 9x² + 8x – 10 para p3 é 41. Exemplo 2 Determine o valor numérico de px = 5x4 – 2x³ + 3x² + 10x – 6, para x = 2. p2 = 5 * 24 – 2 * 23 + 3 * 22 + 10 * 2 – 6 p2 = 5 * 16 – 2 * 8 + 3 * 4 + 20 – 6 p2 = 80 – 16 + 12 + 20 – 6 p2 = 90 De acordo com o polinômio fornecido temos que p2 = pare agora... Tem mais depois da publicidade ;

1 P(x=3) = 4/16 = 1/4 = .25 2. P(x=1 or x=3) = 4/16 + 4/16 = 8/16 = 1/2 = .5 3. P(x=0 or x=1 or x=2) = 1/16 + 4/16 + 6/16 = 11/16 = .6875 4. P(x 3)= 11/16 = .6875, the same as question 3 5. P(x > 2) = 11/16 = .6875. Because 2 is the center event and because of the symmetry of a binomial distribution, this probability is the same as P(x 2) or
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